面试题 03.01 三合一
2022-07-28
1分钟阅读时长
面试题 03.01 三合一
三合一。描述如何只用一个数组来实现三个栈。
你应该实现push(stackNum, value)
、pop(stackNum)
、isEmpty(stackNum)
、peek(stackNum)
方法。stackNum
表示栈下标,value
表示压入的值。
构造函数会传入一个stackSize
参数,代表每个栈的大小。
示例1:
输入: ["TripleInOne", "push", "push", "pop", "pop", "pop", "isEmpty"] [[1], [0, 1], [0, 2], [0], [0], [0], [0]] 输出: [null, null, null, 1, -1, -1, true] 说明:当栈为空时`pop, peek`返回-1,当栈满时`push`不压入元素。
示例2:
输入: ["TripleInOne", "push", "push", "push", "pop", "pop", "pop", "peek"] [[2], [0, 1], [0, 2], [0, 3], [0], [0], [0], [0]] 输出: [null, null, null, null, 2, 1, -1, -1]
提示:
0 <= stackNum <= 2
type TripleInOne struct {
}
func Constructor(stackSize int) TripleInOne {
}
func (this *TripleInOne) Push(stackNum int, value int) {
}
func (this *TripleInOne) Pop(stackNum int) int {
}
func (this *TripleInOne) Peek(stackNum int) int {
}
func (this *TripleInOne) IsEmpty(stackNum int) bool {
}
/**
* Your TripleInOne object will be instantiated and called as such:
* obj := Constructor(stackSize);
* obj.Push(stackNum,value);
* param_2 := obj.Pop(stackNum);
* param_3 := obj.Peek(stackNum);
* param_4 := obj.IsEmpty(stackNum);
*/